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15725781678  15725781678

15725781678

15725781678

15725781678
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#### 废旧电缆 铜芯比重

 核心提示：电缆的价格=制造材料成本+固定费用+税收+业务费+利润 制造材料成本=材料成本*(1+材料消耗)(材料成本即为理论计算出来的值)
YJV成本价格计算公式

YJV铜芯电力电缆系列成本价格公式如下:

=平方数X丝的根数X0.89X当时铜价+10%的加工费。

YJV Cost Price Formula

The cost price formula of YJV copper core power cable series is as follows:

Copper weight X copper price calculation:

Filament diameter 2 = 1.25X1.25X3.14

= The root number of square X filament X0.89X at that time copper price + 10% processing fee.

Cost-Price Formula for Rubber Sheathed Cable

Square X1.83 = weight of copper X The price of copper at that time + price of rubber (weight X0.4 yuan/kg) = cost price + processing fee of 10%.

Cable price = cost of manufacturing materials + fixed cost + tax + business cost + profit

Manufacturing Material Cost = Material Cost * (1 + Material Consumption) (Material Cost is the value calculated theoretically)

Fixed costs vary from company to company, generally including production wages, management wages, utilities, repairs, depreciation, rent and transportation costs.

Formula for Calculating Carrier Flow

"二点五下乘以九，往上减一顺号走"说的是2.5mm'及以下的各种截面铝芯绝缘线，其载流量约为截面数的9倍。如2.5mm'导线，载流量为2.5×9=22.5(A)。从4mm'及以上导线的载流量和截面数的倍数关系是顺着线号往上排，倍数逐次减l，即4×8、6×7、10×6、16×5、25×4。

"三十五乘三点五，双双成组减点五"，说的是35mm"的导线载流量为截面数的3.5倍，即35×3.5=122.5(A)。从50mm'及以上的导线，其载流量与截面数之间的倍数关系变为两个两个线号成一组，倍数依次减0.5。即50、70mm'导线的载流量为截面数的3倍;95、120mm"导线载流量是其截面积数的2.5倍，依次类推。

"条件有变加折算，高温九折铜升级"。上述口诀是铝芯绝缘线、明敷在环境温度25℃的条件下而定的。若铝芯绝缘线明敷在环境温度长期高于25℃的地区，导线载流量可按上述口诀计算方法算出，然后再打九折即可;当使用的不是铝线而是铜芯绝缘线，它的载流量要比同规格铝线略大一些，可按上述口诀方法算出比铝线加大一个线号的载流量。如16mm'铜线的载流量，可按25mm2铝线计算。

" 穿管根数二三四，八七六折满载流"穿管敷设两根、三根、四根电线的情况下，其载流量分别是电工口决计算载流量(单根敷设)的80%、70%、60%。
Estimation formula

Divide it by nine at 2.5 and go up by one.

Thirty-five times three-five, double double group minus five.

Conditions include variable plus conversion and high temperature copper upgrade.

The number of penetrating roots is 234 and 876 are discounted to full current.

Note: The formula in this section does not directly indicate the current carrying capacity (safe current) of various insulating wires (rubber and plastic insulating wires), but is expressed by "multiplying the cross section by a certain number", which is obtained by mental calculation. It can be seen from Table 53 that the multiple decreases with the increase of cross section.

Divide it by nine at 2.5 and go up by one.

"Two-five times nine, one step up and one step down" refers to all kinds of cross-sectional aluminium core insulating wires with 2.5mm'or less, and their carrying capacity is about nine times of the cross-sectional number. For a 2.5mm'conductor, the current carrying capacity is 2.5 x 9 = 22.5 (A). The multiplier relationship between the current carrying capacity and the number of cross sections of conductors above 4mm'is arranged upward along the line number, and the multiplier is reduced by L successively, i.e. 4*8, 6*7, 10*6, 16*5 and 25*4.

Thirty-five times three-five, double double group minus five.

"Thirty-five times three-point-five, double double group minus-five" means that the conductor carrying capacity of 35mm "is 3.5 times of the cross-section number, that is, 35 x 3.5 = 122.5 (A). From 50 mm'or more conductors, the multiplier relationship between the carrying capacity and the cross-section number becomes a group of two line numbers, and the multiplier decreases by 0.5 in turn. That is to say, the carrying capacity of 50 and 70 mm'conductors is three times of the cross-section number; the carrying capacity of 95 and 120 mm conductors is 2.5 times of the cross-section number, and so on.

Conditions include variable plus conversion and high temperature copper upgrade.

"Conditions are converted to change plus, high temperature copper upgrade with 10% discount". The above formula is based on the fact that the insulating wire with aluminium core is laid on the surface at the ambient temperature of 25 C. If the aluminium core insulating wire is laid in the area where the ambient temperature is longer than 25 C, the current carrying capacity of the conductor can be calculated according to the above formula calculation method, and then discounted by 10%. When the copper core insulating wire is used instead of the aluminium wire, its current carrying capacity is slightly larger than that of the aluminium wire of the same specification, the current carrying capacity of the copper core insulating wire can be calculated by the above formula method, which is one line number larger than that of the aluminium wire. If the carrying capacity of 16 mm'copper wire is calculated according to 25 mm 2 aluminum wire.

The number of penetrating roots is 234 and 876 are discounted to full current.

When two, three and four wires are laid through the pipe, the carrying capacity is 80%, 70% and 60% of the calculated carrying capacity (single laying) by the electrician, respectively. 15725781678 